6m^2+2m-4=m

Solution for 6m^2+2m-4=m equation:

6m^2+2m-4=m

We move all terms to the left:

6m^2+2m-4-(m)=0

We add all the numbers together, and all the variables

6m^2+m-4=0

a = 6; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·6·(-4)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{97}}{2*6}=\frac{-1-\sqrt{97}}{12}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{97}}{2*6}=\frac{-1+\sqrt{97}}{12}
$